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Basic Positive-Disp Supercharger Tech and Twin -Screw Compressor Map Analysis

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23K views 37 replies 14 participants last post by  black2003cobra  
#1 · (Edited)
I've finally been able to acquire the compressor "maps" (they're actually just x-y line plots) for the Autorotor MX422 (2.2L) and MX424 (2.4L) superchargers from Opcon. The map for the 2.3L Lysholm (LYS2300AX) is on their web site at: http://www.opconab.com/www/files/lysholm/pdf/performance charts/diagram_lys2300ax.pdf. (Thanks go to Vector for finding those.)

Using the data from these maps, I've gone through and analyzed each while running at the same ambient conditions and the same boost pressure of 1 bar (= 14.5 psi). I also have the maps at lower boost pressures, but I felt there'd be little interest in anything less that 1 bar, so I didn't analyze those. The goal is to look at the volumetric and adiabatic efficiencies, (from which nearly all other performance characteristics can be derived), at the same boost pressure. Since all three of these units are twin-screw designs, it stands to reason that they'd be very similar in these regards.

But before seeing how it comes out, first some background theory and variable definitions, (just in case they're not obvious). Note, subscripts "sc" or "e" imply supercharger or engine, respectively. I've left out all the derivations. I'm only including this to validate the analysis. For those that already know all of this, or if you don't care about the theory and are willing to just take my word for it, feel free to skip it.

VE = volumetric efficiency
AE = adiabatic efficiency
CID = cubic inch displacement (in³)
CFM = volumetric flow rate (ft³/min)
mdot = mass air flow rate (lb/min)
Cp = specific heat of air = 0.34 (HP-sec)/(lb-°F) = 0.0567 (HP-min)/(lb-°F)
ρ = air density (lb/ft³)
ΔT = SC outlet to inlet temperature difference (°F)
Ptot = total manifold pressure (psi)
Pboost = boost pressure (psi)
Patm = atmospheric pressure (psi)
Tamb = ambient temperature (°F)
PR = crank-to-supercharger pulley ratio
HPsc = supercharger drive power (HP)

To keep things simple, assume an ideal intercooler so that Boyle's law can be applied. Therefore, it can be shown that the total manifold pressure (boost pressure plus atmospheric) for these positive-displacement superchargers is given by the expression

(1) Ptot = Patm*(SC air flow rate)/(engine air flow rate) = Patm(CFMsc/CFMe)

The volumetric-flow rate of a positive-displacement supercharger is given by,

(2) CFMsc = VEsc*CIDsc*RPMsc/1728

The volumetric-flow rate for the (4-cycle IC) engine (NA) is given by

(3) CFMe = 0.5*VEe*CIDe*RPMe/1728

Therefore, since RPMsc/RPMe = (crank pulley diameter)/(blower pulley diameter) = PR it follows from (1) - (3) that the total manifold pressure can be written as

(4) Ptot = Patm(2*PR)(VEsc*CIDsc)/(VEe*CIDe)

And boost pressure is simply Pboost = Ptot - Patm. Therefore, since the three compressors all have different displacements, to evaluate VE, AE or supercharger-drive power at the same boost pressure, they must all be spun at different rates, (i.e., with different pulley ratios). To first order, the compressor speed need only be adjusted in inverse proportion to CIDsc relative to that of the "reference" blower. However, since VEsc vs. blower rpm may not be the same for each blower, the boost pressure may not be exactly equal at all speeds while taking this approach. Since the basic designs are the same (twin screw), this is likely to be a second-order effect. Nonetheless, it is what one will actually experience in practice since the pulley ratio is fixed.
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Aside:
If the compressors are spun at the same speeds, clearly the one with the largest effective displacement, (VEsc*CIDsc), would make the most boost, and hence, more net power. (Yes, power and torque are increased by increasing the mass of air and fuel going into the engine, but that doesn't mean that boost pressure is meaningless - for a given engine, exhaust system, etc., increasing boost is a simple and effective way of increasing the mass of air and fuel that's going into the engine. To be sure, improving the volumetric efficiency of the engine is more efficient since there's no drive power penalty or extra heating, but let's dispel the myth that boost pressure is meaningless.)
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Alternatively, VE, AE or HPd of the different blowers can all be plotted vs. the volume-flow rate (CFMsc). Although this insures the same boost pressure between the blowers at any given flow rate, this isn't physically realizable in practice. However, it makes the analysis easier since the data can be taken right off the maps without having to scale the blower speeds.

Therefore, since the blowers are all run at the same boost pressure and the intercooler is assumed ideal, (i.e., IAT2 = ambient temp), net engine power produced will only be dependent on any difference in drive power req'd by the different compressors.

Now if the compressors were ideal, they would all consume the same amount of energy to compress the air since boost pressure is constant. This process is referred to as adiabatic compression wherein by definition, no heat is lost (or gained) from the surroundings and hence, all of the mechanical energy required to compress the air is converted to heat energy which raises the temperature at the outlet of the supercharger. (Yes, I know there is an intercooler here, but this doesn't change the definition of adiabatic compression. And it still takes energy to compress the air, which is converted into heat energy, and then thrown away by the intercooler. Hence, there's still a power loss.) This increase in temperature is the theoretical minimum that can be achieved, and is a function of the boost pressure, and inlet pressure and temperature. However, in reality, there will always be some friction (both mechanical and air friction), which results in additional heat and hence, power loss. Since frictional losses are not necessarily the same for each blower, the extra power consumed due to these losses may not necessarily be the same for each blower. These additional frictional losses are characterized by the so-called adiabatic efficiency. The adiabatic efficiency is defined as the adiabatic drive power divided by the actual drive power, or by the adiabatic temp rise divided by the actual temp rise. These are equivalent definitions. It can be shown that the temp rise from the inlet to outlet is given by

(5) ΔT = (460 + Tamb)[(1 + Pboost/Patm)^(2/7) - 1]/AE

And that the SC drive power loss is given by

(6) HPsc = mdot*Cp*ΔT

where mdot is the mass-air flow rate in lb/min as given by

(7) mdot = ρ*CFMsc

and ρ is the ambient air density in lb/ft³.

What's not included in the analysis? Note that HPsc as given by (6) does not include any inertial losses. The primary inertial power loss would go as usual, by P = I*α*ω where I = mass moment of inertia of the rotors, α = angular acceleration (rad/sec²), and ω = angular velocity (rad/sec). In general, since the larger blower will have larger rotors, their mass moment of inertia would generally tend to be larger. But since the compressors would have to be spun at a lower speed for the same boost pressure on a given engine, this would tend to cancel the increased moment. Other internal design changes could change all this, however. There are other factors that occur in the real world that don't come in to play during the testing used to generate these blower maps, which can change the final results also. For example, there isn't an infinite number of pulley sizes available to choose from. Therefore, one would not necessarily be able to run the various SCs at the same boost levels in practice. As another example, any real intercooler isn't 100% efficient either. As a result, a blower with a higher AE will result in a lower IAT2. Obviously the lower the IAT2 at a given boost pressure, the denser the air and the more power will be produced. (However, since mdot had to go up to maintain the same boost pressure at the lower IAT2, so does the drive power, which tends to offset some of the gain.) A lower IAT2 may also cause the ECU to add more timing (depending on the max total timing commanded, etc.) resulting in an increase in power. All these sorts of things are left out. The above analysis only takes into account the differences of AE and VE of the blowers as reported on the compressor maps available in the public domain. The maps for all three blowers came directly from the respective manufacturers. If the data on these maps is inaccurate or not reflective of typical product for some reason, then obviously the end results can be different. I'm only reporting here based on the data found in those maps. The results may also be different at different boost levels.

Compared to the stock Roots-type Eaton supercharger, all three of these blower upgrades are a big improvement! A previous analysis of the 2.3L Lysholm and Eaton M112 can be found here (see post #16&17): http://www.modularfords.com/showthread.php?t=16208

And here's a link to a related thread that you may find of interest.
http://www.modularfords.com/2003-20...eness-of-engine-ve-changes-with-a-positive-displacement-supercharger-41735.html

OK…but enough of all that - on to the results. The first graph shows the VE and AE vs. CFMsc for the Lysholm 2.3L and Autorotor 2.2L compressors, and the second graph shows the resulting drive power vs. air flow. The same ambient conditions and boost pressure are used in both cases. Again, no inertial losses are included. The third and fourth graphs show these same parameters for the Lysholm 2.3L and Autorotor 2.4L compressors, again at a boost pressure of 1 bar = 14.5 psi.
 

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#3 ·
Yes, the supercharger drive power is the power it takes to run the blower. In terms of VE and AE, you'd like those to be high. The volumetric efficiency tells you how much air (volume-wise) the blower is actually ingesting per revolution compared to the "geometrical" displacement of the blower. Same definition as for an NA engine. The adiabatic efficiency tells you how much extra heating (from friction) is going on relative the theoretical minimum (from just compressing the air). Sorry it's long. I know it might be a lot to digest.
 
#6 ·
That's really good, thanks!

Interesting to note that the 2.4L didn't really stack up that well against the 2.3L.

Do you think it's because the relatively low boost level is better matched to the 2.3L?

It'd be interesting to plot the 2.2 and 2.4 to see the similarities there; are the curves a product of KB's rotor design?

Am I reading those graphs correctly?

Thanks again.

Mike
 
#7 ·
EatonEggbeater said:
That's really good, thanks!

Interesting to note that the 2.4L didn't really stack up that well against the 2.3L.

Do you think it's because the relatively low boost level is better matched to the 2.3L?

It'd be interesting to plot the 2.2 and 2.4 to see the similarities there; are the curves a product of KB's rotor design?

Am I reading those graphs correctly?

Thanks again.

Mike
didn't KB say that theh 2.4 shines in high boost but is very similar to 2.2 in lower boost? i'm not talking about pulley sizes now, actual boost psi.

I also find it interestng how close the VE is but the AE is quite different...i ahve no clue what that means but it has to mean something...lol
 
#8 ·
You know…I was initially unsure if I should post this stuff, but I can now see that there is a genuine interest. And thanks for keeping it constructive and civil!

As far as overlaying the Eaton curve on the ones here, it’s not really fair since that comparison was done at 10 psi. I’d need the data for the M112 at 14.5 psi to be able to do that. (I could estimate the change in efficiencies, but I’d prefer not to as I don’t like to extrapolate beyond the point where I have data.)

I did overlay the 2.2L and 2.4L Autorotor, and the VE curves lie right on top of one another. The AE of the 2.4L was actually higher at a given flow rate (perhaps because it is not spinning as fast so not as much mech friction would be my guess), thereby resulting in less drive power. That’s actually a good example of how AE affects drive power and why you want to have AE as high as possible! (I can post the graphs if you want. Let me know.)

And yes, at lower boost levels, the situation changes. Actually, at stock boost levels and relatively low rpm, the stock Eaton has a higher VE than the 2.3L Lysholm as you can see in the graph in that other thread.
 
#9 · (Edited)
black2003cobra said:
And yes, at lower boost levels, the situation changes. Actually, at stock boost levels and relatively low rpm, the stock Eaton has a higher VE than the 2.3L Lysholm as you can see in the graph in that other thread.
One thing this post does is put a scientific end to the "KB2.2/Whipple2.3/KB2.4 Roots/Autorotor/Lysholm; which is best" debate.
The answer depends on boost level and rpm range.

Thanks for the work, and if it's not too much trouble to post the 2.2/2.4 overlay that'd be nice. Evidently, the KB's either have one more lobe on the rotor, or one less than the Whipple, I wonder where that shows up, if it does at all? I don't think the compressor maps have (or need, really) any reference to inertial loading, so that's not a factor. I'm going to go over your post again looking for anything factoring in mass relativity, can't read & post at the same time!...
Very interesting stuff you've gotten to.

Mike

-Edit- changed my sig...
-Edit2- I see where you've addressed inertia, reading that now.
 
#10 ·
black2003cobra said:
You know…I was initially unsure if I should post this stuff, but I can now see that there is a genuine interest. And thanks for keeping it constructive and civil!
Great detail.. Not sure if the thread will get ugly ..

Anyway, I wonder how a 2.3l shows better results over the 2.2l(in almost every situation) yet the 2.4l shows barely better or worse than the 2.3l in many situations?

Your thoughts? I can see this being a kb bashing point...
 
#11 ·
Also-

Your analysis only takes into account the data given from the said screw sets. I.E. no information is relevant to our cars other than the data about the screws and the case they sit in.

No information about the inlet castings or the blower-to-lower billet adapter. They will have some impact on the final performance as well.

Just wanted to make that point

:thumbsup
 
#13 ·
Bottom line, at 14 PSI, Whipple/Lysholm is a better twin-screw compressor. Which I think we all pretty much knew.

But, it's so close, it really doesn't matter. Practically speaking, they are identical compressors. Pick which one gets your juices flowing and enjoy it.
 
#14 ·
Just going from the compressor efficiency side, would those maps give any information for optimal boost levels for a particular blower?

For example, running a KB 2.4 at only 1 atm. pressure is almost certainly a misapplication, does the data suggest an optimum boost for the compressors compared? The 2'nd derivitave of the AE curve, maybe?
 
#15 ·
I probably won’t be able to get back to this thread until much later today, or possibly tomorrow. But I just wanted to quickly comment about the thread getting “ugly”. This is in our control! If we keep it purely technical, (as has been the case so far), that shouldn’t happen. Please let’s try to keep it that way so what can hopefully be a useful thread doesn’t get locked down. JKD said he will keep an eye on it – please don’t give him any reason to shut it down! Thanks!
 
#17 ·
black2003cobra said:
As far as overlaying the Eaton curve on the ones here, it's not really fair since that comparison was done at 10 psi. I'd need the data for the M112 at 14.5 psi to be able to do that. (I could estimate the change in efficiencies, but I'd prefer not to as I don't like to extrapolate beyond the point where I have data.)
I understand. :beerchug:
 
#18 ·
OK...I have time to answer a couple questions and then I have to run off to a meeting.

What does having a higher (or lower) VE mean at a given flow rate?

Since the VE plots as shown above are made vs. volumetric-flow rate to insure a constant boost pressure (for comparison purposes, only), the interpretation is as follows by way of example. Consider two hypothetical blowers with the same geometrical displacement CIDsc_a = CIDsc_b = CIDsc, but where blower A has a higher VE at low flow rates and blower B has a higher VE at high flow rates. Also assume that VE_a = VE_b right in the middle of the rpm range (say, at RPM_mid) and that the pulley ratio is identical. This means both blowers will be making the same amount of boost at this mid-range engine speed, (since VE_a*CIDsc*PR*RPM_mid = VE_b*CIDsc*PR*RPM_mid). Therefore, since blower A will be flowing more air at lower engine speeds (since VE_a*CIDsc > VE_b*CIDsc at low rpm), then it will be making more boost at RPM < RPM_mid. Conversely, blower B will make more boost at higher rpm by the same argument. This is a good question because it gets back to the fact that the supercharger should be selected and properly sized depending on application. For example, for applications where low-end grunt is needed, such as towing, you want a blower that will flow more air down at low engine speeds. For drag racing, on the other hand, you want to make more boost where peak power is. Since typically a larger blower will have a lower VE at low speeds and flow rates, these are not really suitable for street or towing applications. This is why often times manufactures will spec both minimum and maximum flow rates to help the user determine which is best for their application. So for relatively low (stock) boost levels for street applications, the stock Eaton is the better choice, IMO. But yes&#8230;at high boost pressures, the Eaton's VE and AE really start to go in the toilet. That's where the twin-screws really shine!

Can the compressor maps be used to help you select the right blower?

Absolutely! This is exactly why they are so useful. On the more "typical" type of compressor map, which typically show VE and AE contours (lines of constant VE or AE) plotted on a graph of pressure ratio vs. flow rate, one would want to look at where the "islands" of higher efficiency are located, (i.e., at what particular pressure ratio and flow rate), for the various blowers being considered for the particular application. Note, pressure ratio = (outlet pressure)/(inlet pressure) = Poutlet/Pinlet, so since Pboost = (Poutlet - Patm), and since Pinlet = Patm, it follows that Pboost = Patm*[(pressure ratio) - 1]. I'm really sorry for all this math guys, but I don't know how else to do it.
 
#19 ·
2.4L and 2.2L Autorotor graphs at 14.5 psi.

Here are those other graphs.
 

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#20 · (Edited)
While trying to get a better hold on Volumetric Efficiency, and Adiabatic Efficiency, I ran into this comparison

Roots, Lysholm and Centrifugal superchargers explained

If I'm right, VE is a ratio of volume in to volume out for a particular RPM, and AE is more related to thermal ineficiencies, inlet temperature to outlet temperature as a percentage of a "Perfect compressor" output. Rather than tie your fingers (and my brain) up, can you suggest a website where I can spend a little time bringing myself up to inadequate, and maybe read through your first post again?

Anybody seen my tinfoil hat?!

-Edit- From the 2 new graphs, it looks like what lRageATMl posted above, the gist being that if you're going to stay at lower boost levels, the 2.2 is marginally better than the 2.4, especially if you factor in cost.
 
#21 ·
Mike - VE is defined as the actual volumetric-flow rate divided by the maximum theoretical (or geometrical) volumetric-flow rate. You nailed the definition of AE – it is the minimum theoretical outlet temp divided by the actual outlet temp, (where the theoretical min outlet temp is as determined from ideal, adiabatic compression.) An alternative, but equivalent definition for AE is theoretical minimum drive power divided by the actual drive power. Not sure if I can point you to any good web sites, off hand. I guess I’d just try doing a search on the two terms and see what that turns up.

Oh, and Wilson, yes - absolutely…this analysis does not include any affect on VE from the inlet casting, or extra heating from air turbulence under the intercooler, etc. Just the rotor packs themselves are considered.
 
#24 ·
Thanks Vector and Kevin. I hope people find this info useful.

Oh, and an interesting side note, the internal or built-in pressure ratio of the Lysholm is given as Rp,int = 1.35 and the Autorotor "maps" give Rp,int = 1.4 (although I don't know if they're perhaps just rounding off 1.35 to 1.4.) Any way, this means that only 5-6 psi of boost is actually created between the screws. (Built-in boost = Patm[Rp,int - 1]). The remainder is created buy building up pressure within the intake manifold, just as is done with the Roots-type blowers.
 
#26 ·
purevil said:
Whith all of this knowledge, can somone explain to me how the blower knows what pulley is on to go to a specific level of boost.
Obviously the blower doesn't know. You have to select the correct pulley ratio to spin the blower at the appropriate speed (relative to that of the engine) so that its volumetric-flow rate is what is required to achieve a specific boost level (on a particular engine) you're looking for. See equations (1) - (4).